Play it again, Sam!
What if 90% of the sick days were on Monday or Friday?
degrees of freedom | Χ2 crit for α = 0.055 |
---|---|
1 | 3.84 |
2 | 5.99 |
3 | 7.81 |
4 | 9.49 |
5 | 11.07 |
6 | 12.59 |
7 | 14.07 |
8 | 15.51 |
9 | 16.92 |
10 | 18.31 |
Ok, so now take that calculated chi-squared value and compare it to the critical chi square value on the table.
You should have got a chi-squared statistic of 104.166, compared to the chi-squared critical value of 3.84. The chi-squared statistic is much greater than the chi-squared critical value-- so the data does not fit the model and you reject your null hypothesis. In other words, Dilbert's random sick day model does NOT hold up.
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