MathBench > Statistical Tests

Chi-squared Tests

Play it again, Sam!

What if 90% of the sick days were on Monday or Friday?

observed ("o") expected ("e") (o-e) (o-e)2 (o-e)2/e
Monday or Friday
Midweek
Total 100 100    
Check

 

degrees of freedom Χ2 crit for α = 0.055
1 3.84
2 5.99
3 7.81
4 9.49
5 11.07
6 12.59
7 14.07
8 15.51
9 16.92
10 18.31

Ok, so now take that calculated chi-squared value and compare it to the critical chi square value on the table.

 

 

You should have got a chi-squared statistic of 104.166, compared to the chi-squared critical value of 3.84. The chi-squared statistic is much greater than the chi-squared critical value-- so the data does not fit the model and you reject your null hypothesis. In other words, Dilbert's random sick day model does NOT hold up.