Play it again, Sam!
What if 90% of the sickdays were on M/F?
Ok, so now take that calculated chi square value and compare it to the critical chi square on the table.
You should have gotten a chi-square-calc of 104.166, compared to the chi-square-crit of 3.84. So, the chi-square-calc is much greater than the chi-square-crit -- so the data does not fit the model and you reject your null hypothesis. In other words, the engineer's random sickday model does NOT hold up.
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